[ AFMC 1991]
A) $ ML^{2}{{T}^{-2}} $
B) $ M^{2}L{{T}^{-1}} $
C) $ ML^{2}{{T}^{-1}} $
D) $ ML^{3}{{T}^{-1}} $
Correct Answer: A
Kinetic energy = $ \frac{1}{2}mv^{2}=M{{[L{{T}^{-1}}]}^{2}}=[ML^{2}{{T}^{-2}}] $
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