Optics Question 969

Question: A diver at a depth of 12m in water ( $ \mu =4/3) $ sees the sky in a cone of semi-vertical angle

[KCET 1999; Pb. PMT 2002; MP PMT 1995, 2003]

Options:

A) $ {{\sin }^{-1}}(4/3) $

B) $ {{\tan }^{-1}}(4/3) $

C) $ {{\sin }^{-1}}(3/4) $

D) 90°

Show Answer

Answer:

Correct Answer: C

Solution:

Semi vertical angle $ =C={{\sin }^{-1}}( \frac{1}{\mu } )={{\sin }^{-1}}( \frac{3}{4} ) $



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