SATHEE: Optics Question 946

Optics Question 946

Question: A prism of dispersive power 0.021 and refractive index 1.53 form an achromatic combination with prism of angle $4.2^{\circ}$ and dispersive power 0.045 having refractive index 1.65. Find the resultant deviation.

Options:

A) $1.12^{\circ}$

B) $2.16^{\circ}$

C) $3.12^{\circ}$

D) $4.18^{\circ}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Here, $ω = 0.021; μ = 1.53; ω ‘ = 0.045;$ $μ ‘ = 1.65;$

$A^{'} = {4.2}^{o}$

For no dispersion, $ω δ + δ ‘ δ ‘ = 0$

or $ω A (μ - 1) + ω ‘ A^{'} (μ - 1) = 0$

or $A = - \frac{ω ‘ A^{'} (μ ‘ - 1)}{θ (μ - 1)}$

$= \frac{0.045 \times 4.2 (1.65 - 1)}{0.02 \times (1.53 - 1)} = - {11.04}^{o}$

Net deviation,

$δ + δ ‘ = A (μ - 1) + A^{'} (μ ‘ - 1)$

$= - 11.04 (1.53 - 1) + 4.2 (1.65 - 1)$

$= - 11.04 \times 0.53 + 4.2 \times 0.65$

$= - 5.85 + 2.73 = {3.12}^{o}$

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Optics Question 946

Question: A prism of dispersive power 0.021 and refractive index 1.53 form an achromatic combination with prism of angle 4.2∘ and dispersive power 0.045 having refractive index 1.65. Find the resultant deviation.

Options:

Answer:

Solution:

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Question: A prism of dispersive power 0.021 and refractive index 1.53 form an achromatic combination with prism of angle $4.2^{\circ}$ and dispersive power 0.045 having refractive index 1.65. Find the resultant deviation.