SATHEE: Optics Question 908

Optics Question 908

Question: In a concave mirror experiment, an object is placed at a distance $x_{1}$ from the focus and the image is formed at a distance $x_{2}$ from the focus. The focal length of the mirror would be

[MP PET 1997]

Options:

A) $x_{1} x_{2}$

B) $\sqrt{x_{1} x_{2}}$

C) $\frac{x_{1} + x_{2}}{2}$

D) $\sqrt{\frac{x_{1}}{x_{2}}}$

Show Answer

Answer:

Correct Answer: B

Solution:

Given $u = (f + x_{1})$ and $v = (f + x_{2})$

The focal length $f = \frac{u v}{u + v} = \frac{(f + x_{1}) (f + x_{2})}{(f + x_{1}) + (f + x_{2})}$

On solving, we get $f^{2} = x_{1} x_{2}$ or $f = \sqrt{x_{1} x_{2}}$

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Optics Question 908

Question: In a concave mirror experiment, an object is placed at a distance x1 from the focus and the image is formed at a distance x2 from the focus. The focal length of the mirror would be

Options:

Answer:

Solution:

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Question: In a concave mirror experiment, an object is placed at a distance $x_{1}$ from the focus and the image is formed at a distance $x_{2}$ from the focus. The focal length of the mirror would be