Optics Question 900

Question: In Young’s double-slit experiment, let A and B be the two slits. A thin film of thickness t and refractive index [i is placed in front of A. Let $ \beta =frings $ width. Then the central maxima will shift

Options:

A) toward A

B) toward B

C) by $ t(\mu -1)\frac{\beta }{\lambda } $

D) by $ \mu t\frac{\beta }{\lambda } $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] For central maximum at P, $ \frac{xd}{D}=t(\mu -1) $ or $ x=t(\mu -1)\frac{D}{d} $ .

Now, $ \beta =\frac{D\lambda }{d} $

$ \therefore \frac{D}{d}=\frac{\beta }{\lambda } $ .

Hence, $ x=t(\mu -1)\frac{\beta }{\lambda } $



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