Optics Question 90

Question: A ray of light is incident at the glass?water interface at an angle i, it emerges finally parallel to the surface of water, then the value of $ {\mu _{g}} $ would be

[IIT-JEE (Screening) 2003]

Options:

A) (4/3) sin i

B) 1/sin i

C) 4/3

D) 1

Show Answer

Answer:

Correct Answer: B

Solution:

For glass-water interface $ _{g}{\mu _{w}}=\frac{\sin i}{\sin r} $ -(i) For water-air interface $ _{w}{\mu _{a}}=\frac{\sin r}{\sin 90^{o}} $ -(ii)

$ \Rightarrow $ $ _{g}{\mu _{w}}\times _{w}{\mu _{a}}=\frac{\sin i}{\sin r}\times \frac{\sin r}{\sin 90^{o}}=\sin i $

$ \Rightarrow $ $ \frac{{\mu _{w}}}{{\mu _{g}}}\times \frac{{\mu _{a}}}{{\mu _{w}}}=\sin i\Rightarrow {\mu _{g}}=\frac{1}{\sin i} $



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