Optics Question 892
Question: The angle of polarisation for any medium is $ 60{}^\circ $ The critical angle for this is
Options:
A) $ {{\sin }^{-1}}\frac{1}{\sqrt{3}} $
B) $ {{\cos }^{-1}}\sqrt{3} $
C) $ {{\sin }^{-1}}\sqrt{3} $
D) $ {{\tan }^{-1}}\sqrt{3} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ \mu =\tan i _{p}=\tan 60^{o}=\sqrt{3} $
$ \sin i _{C}=\frac{1}{\mu }=\frac{1}{\sqrt{3}}\Rightarrow i _{C}={{\sin }^{-1}}\frac{1}{\sqrt{3}} $
