Optics Question 867

Question: In young’s double - slit experiment, the separation between the slits is d, distance between the slit and screen is D (D»d). In the interference pattern, there is a maxima exactly in front of each slit. Then the possible wavelength(s) used in the experiment are

Options:

A) d2/D,d2/2D,d2/3D

B) d2/D,d2/3D,d2/5D

C) d2/2D,d2/4D,d2/6D

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

[c] S2PS1P=dyD=d×(d/2)D=d22D

d22D=nλ

λ=d2nD , n=1, 2, ??.. λ=d22D,d24D,d26D



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