SATHEE: Optics Question 849

Optics Question 849

Question: In Fresnel’s biprism experiment the width of 10 fringes is 2cm which are formed at a distance of 2 meter from the slit. If the wavelength of light is $5100 \overset{o}{A}$ then the distance between two coherent sources will be

Options:

A) $5.1 \times 10^{- 4} m$

B) $5.1 \times 10^{4} m$

C) $5.1 \times 10^{- 4} m m$

D) $10.1 \times 10^{- 4} c m$

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Answer:

Correct Answer: A

Solution:

[a] $d = \frac{D λ}{β}$ …(i)

According to question, $λ = 5100 \times 10^{- 10} m$

$β = \frac{2}{10} \times 10^{- 2} m$ …(ii) D=2m, d=?

From eqs. (i) and (ii) $d = \frac{2 \times 51 \times 10^{- 8}}{2 \times 10^{- 3}} = 5.1 \times 10^{- 4} m$

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Optics Question 849

Question: In Fresnel’s biprism experiment the width of 10 fringes is 2cm which are formed at a distance of 2 meter from the slit. If the wavelength of light is $5100 \overset{o}{A}$ then the distance between two coherent sources will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Optics Question 849

Question: In Fresnel’s biprism experiment the width of 10 fringes is 2cm which are formed at a distance of 2 meter from the slit. If the wavelength of light is 5100Ao then the distance between two coherent sources will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: In Fresnel’s biprism experiment the width of 10 fringes is 2cm which are formed at a distance of 2 meter from the slit. If the wavelength of light is $5100 \overset{o}{A}$ then the distance between two coherent sources will be