SATHEE: Optics Question 832

Optics Question 832

Question: A telescope has an objective lens of focal length 150 cm and an eyepiece of focal length 5 cm. If a 50 m tall tower at a distance of 1 km is observed through this telescope in normal setting, the angle formed by the image of the tower is $θ$ , then $θ$ is close to :

Options:

A) 6.1 rad

B) 3.2 rad

C) 1.5 rad

D) 0.2 rad

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Magnifying power of telescope, $M P = \frac{β (angle subtended by image at eye piece)}{α (angle subtended by object on objective)}$ Also, $M P = \frac{f_{0}}{f_{e}} = \frac{150}{5} = 30 α = \frac{50}{1000} = \frac{1}{20} r a d$

$∴ β = θ = M P \times α = 30 \times \frac{1}{20} = \frac{3}{2} = 1.5 r a d$

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Optics Question 832

Question: A telescope has an objective lens of focal length 150 cm and an eyepiece of focal length 5 cm. If a 50 m tall tower at a distance of 1 km is observed through this telescope in normal setting, the angle formed by the image of the tower is θ , then θ is close to :

Options:

Answer:

Solution:

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Question: A telescope has an objective lens of focal length 150 cm and an eyepiece of focal length 5 cm. If a 50 m tall tower at a distance of 1 km is observed through this telescope in normal setting, the angle formed by the image of the tower is $θ$ , then $θ$ is close to :