Optics Question 680

Question: A point object is placed at the center of a glass sphere of radius 6 cm and refractive index 1.5. The distance of the virtual image from the surface of the sphere is

[IIT-JEE (Screening) 2004]

Options:

A) 2 cm

B) 4 cm

C) 6 cm

D) 12 cm

Show Answer

Answer:

Correct Answer: C

Solution:

Using refraction formula $ \frac{ _{1}{\mu _{2}}-1}{R}=\frac{ _{1}{\mu _{2}}}{v}-\frac{1}{u} $ in given case, medium (1) is glass and (2) is air .

So $ \frac{ _{g}{\mu _{a}}-1}{R}=\frac{ _{g}{\mu _{a}}}{v}-\frac{1}{u} $

$ \Rightarrow \frac{\frac{1}{1.5}-1}{-6}=\frac{1}{1.5v}-\frac{1}{-6} $

$ \Rightarrow \frac{1-1.5}{-6}=\frac{1}{v}+\frac{1.5}{6} $

$ \Rightarrow \frac{0.5}{6}=\frac{1}{v}+\frac{1}{4} $

$ \Rightarrow \frac{1}{v}=\frac{1}{12}-\frac{1}{4}=-\frac{2}{12}=-\frac{1}{6} $

Therefore v = 6 cm



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