Optics Question 633
Question: The image distance of an object placed 10 cm in front of a thin lens of focal length + 5 cm is
[SCRA 1994]
Options:
A) 6.5 cm
B) 8.0 cm
C) 9.5 cm
D) 10.0 cm
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{1}{f}=\frac{1}{v}-\frac{1}{u} $
$ \Rightarrow $ $ \frac{1}{+5}=\frac{1}{v}-\frac{1}{(-10)}\Rightarrow v=10 $ $ cm $
