Optics Question 604

Question: The radius of curvature of convex surface of a thin plano-convex lens is 15 cm and refractive index of its material is 1.6. The power of the lens will be

[MP PMT 1994]

Options:

A) $ +1D $

B) $ -2D $

C) $ +3D $

D) $ +4D $

Show Answer

Answer:

Correct Answer: D

Solution:

$ f=\frac{R}{(\mu -1)}=\frac{15}{(1.6-1)}=25cm $

$ \therefore P=\frac{100}{f}=\frac{100}{25}=+4D $



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