SATHEE: Optics Question 601

Optics Question 601

Question: A double convex thin lens made of glass (refractive index $μ$ = 1.5) has both radii of curvature of magnitude 20 cm. Incident light rays parallel to the axis of the lens will converge at a distance L such that

[MNR 1991; MP PET 1996; UPSEAT 2000; Pb PET 2004]

Options:

A) L = 20 cm

B) L = 10 cm

C) L = 40 cm

D) L = 20 / 3 cm

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Answer:

Correct Answer: A

Solution:

$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

Given $R_{1} = + 20 c m, R_{2} = - 20 c m$ , $μ = 1.5$

$\Rightarrow$ $f = 20$ $c m$ . Parallel rays converge at focus. So L=f.

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Optics Question 601

Question: A double convex thin lens made of glass (refractive index $μ$ = 1.5) has both radii of curvature of magnitude 20 cm. Incident light rays parallel to the axis of the lens will converge at a distance L such that

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Optics Question 601

Question: A double convex thin lens made of glass (refractive index μ = 1.5) has both radii of curvature of magnitude 20 cm. Incident light rays parallel to the axis of the lens will converge at a distance L such that

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: A double convex thin lens made of glass (refractive index $μ$ = 1.5) has both radii of curvature of magnitude 20 cm. Incident light rays parallel to the axis of the lens will converge at a distance L such that