SATHEE: Optics Question 600

Optics Question 600

Question: An object is placed at a distance of $f / 2$ from a convex lens. The image will be

[CPMT 1974, 89]

Options:

A) At one of the foci, virtual and double its size

B) At 3f / 2, real and inverted

C) At 2f, virtual and erect

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$ (Given $u = \frac{- f}{2}$ )

$\Rightarrow$ $\frac{1}{f} = \frac{1}{v} + (\frac{1}{f / 2}) \Rightarrow \frac{1}{v} = \frac{1}{f} - \frac{2}{f}$

$\Rightarrow$ $\frac{1}{v} = \frac{- 1}{f}$ and $m = \frac{v}{u} = \frac{f}{f / 2} = 2$ So virtual at the focus and of double size.

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Optics Question 600

Question: An object is placed at a distance of $f / 2$ from a convex lens. The image will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Optics Question 600

Question: An object is placed at a distance of f/2 from a convex lens. The image will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: An object is placed at a distance of $f / 2$ from a convex lens. The image will be