SATHEE: Optics Question 574

Optics Question 574

Question: Two polaroids are placed in the path of unpolarized beam of intensity $I_{0}$ such that no light is emitted from the second polaroid. If a third polaroid whose polarization axis makes an angle q with the polarization axis of first polaroid, is placed between these polaroids then the intensity of light emerging from the last polaroid will be

[UPSEAT 2005]

Options:

A) $(\frac{I_{0}}{8}) \sin^{2} 2 θ$

B) $(\frac{I_{0}}{4}) \sin^{2} 2 θ$

C) $(\frac{I_{0}}{2}) \cos^{4} θ$

D) $I_{0} \cos^{4} θ$

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Answer:

Correct Answer: A

Solution:

No light is emitted from the second polaroid, so $P_{1}$ and $P_{2}$ are perpendicular to each other

Let the initial intensity of light is $I_{0}$ .

So Intensity of light after transmission from first polaroid = $\frac{I_{0}}{2}$ .

Intensity of light emitted from $P_{3}$

$I_{1} = \frac{I_{0}}{2} \cos^{2} θ$ Intensity of light transmitted from last polaroid i.e. from $P_{2} = I_{1} \cos^{2} (90^{o} - θ)$ = $\frac{I_{0}}{2} \cos^{2} θ . \sin^{2} θ$

$= \frac{I_{0}}{8}$

${(2 \sin θ \cos θ)}^{2}$ = $\frac{I_{0}}{8} \sin^{2} 2 θ$ .

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Optics Question 574

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

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सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Optics Question 574

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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