Optics Question 477

Question: An electric bulb illuminates a plane surface. The intensity of illumination on the surface at a point 2m away from the bulb is $ 5\times {{10}^{-4}} $ phot (lumen/cm2). The line joining the bulb to the point makes an angle of 60o with the normal to the surface. The intensity of the bulb in candela is

[IIT-JEE 1980; CPMT 1991]

Options:

A) $ 40\sqrt{3} $

B) 40

C) 20

D) $ 40\times {{10}^{-4}} $

Show Answer

Answer:

Correct Answer: B

Solution:

$ I=\frac{L\cos \theta }{r^{2}} $

$ \Rightarrow \ \ L=\frac{I\times r^{2}}{\cos \theta } $

$ =\frac{5\times {{10}^{-4}}\times 10^{4}\times 2^{2}}{\cos 60{}^\circ }\ =\ 40\ Candela $



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