Optics Question 440

Question: A compound microscope has an eye piece of focal length 10 cm and an objective of focal length 4 cm. Calculate the magnification, if an object is kept at a distance of 5 cm from the objective so that final image is formed at the least distance vision (20 cm)

[UP SEAT 2005]

Options:

A) 12

B) 11

C) 10

D) 13

Show Answer

Answer:

Correct Answer: A

Solution:

For objective lens $ \frac{1}{f _{o}}=\frac{1}{v _{o}}-\frac{1}{u _{o}} $

Therefore $ \frac{1}{v _{o}}=\frac{1}{f _{o}}+\frac{1}{u _{o}} $

$ =\frac{1}{4}+\frac{1}{-5}=\frac{1}{20} $

Therefore $ v _{o}=20cm $ Now $ M=\frac{v _{o}}{u _{o}}( 1+\frac{D}{f _{e}} ) $

$ =\frac{20}{5}( 1+\frac{20}{10} ) $

$ =12. $



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