Optics Question 376

Question: A simple telescope, consisting of an objective of focal length 60 cm and a single eye lens of focal length 5 cm is focussed on a distant object is such a way that parallel rays comes out from the eye lens. If the object subtends an angle 2o at the objective, the angular width of the image

[CPMT 1979; NCERT 1980; MP PET 1992; JIPMER 1997; UPSEAT 2001]

Options:

A) 10o

B) 24o

C) 50o

D) 1/6o

Show Answer

Answer:

Correct Answer: B

Solution:

Since $ m=\frac{f _{o}}{f _{e}} $ Also $ m=\frac{Angle\ subtended\ by\ the\ image}{Angle\ subtended\ by\ the\ object} $

$ \therefore \frac{f _{o}}{f _{e}}=\frac{\alpha }{\beta } $

$ \Rightarrow \alpha =\frac{f _{o}\times \beta }{f _{e}}=\frac{60\times 2}{5}=24^{o} $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक