Optics Question 362
Question: In a compound microscope, the focal lengths of two lenses are 1.5 cm and 6.25 cm an object is placed at 2 cm form objective and the final image is formed at 25 cm from eye lens. The distance between the two lenses is
[EAMCET (Med.) 2000]
Options:
A) 6.00 cm
B) 7.75 cm
C) 9.25 cm
D) 11.00 cm
Show Answer
Answer:
Correct Answer: D
Solution:
$ L=v _{o}+u _{e}=\frac{u _{o}f _{o}}{(u _{o}-f _{o})}+\frac{f _{e}D}{f _{e}+D} $
$ \Rightarrow L=\frac{2\times 1.5}{(2-1.5)}+\frac{6.25\times 25}{(6.25+25)}=11\ cm $
