Optics Question 343

Question: The focal length of objective and eye lens of a microscope are 4 cm and 8 cm respectively. If the least distance of distinct vision is 24 cm and object distance is 4.5 cm from the objective lens, then the magnifying power of the microscope will be

Options:

A) 18

B) 32

C) 64

D) 20

Show Answer

Answer:

Correct Answer: B

Solution:

For objective lens $ \frac{1}{f _{o}}=\frac{1}{v _{o}}-\frac{1}{u _{o}} $

$ \Rightarrow \frac{1}{(+4)}=\frac{1}{v _{o}}-\frac{1}{(-4.5)} $

$ \Rightarrow v _{o}=36\ cm $

$ \therefore |m _{D}|\ =\frac{v _{o}}{u _{o}}( 1+\frac{D}{f _{e}} )=\frac{36}{4.5}( 1+\frac{24}{8} )=32 $



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