Optics Question 324

Question: Radiations of intensity $ 0.5W/m^{2} $ are striking a metal plate. The pressure on the plate is

[DCE 2004]

Options:

A) $ 0.166\times {{10}^{-8}}N/m^{2} $

B) $ 0.332\times {{10}^{-8}}N/m^{2} $

C) $ 0.111\times {{10}^{-8}}N/m^{2} $

D) $ 0.083\times {{10}^{-8}}N/m^{2} $

Show Answer

Answer:

Correct Answer: A

Solution:

Intensity or power per unit area of the radiations $ P=fv $

Therefore $ f=\frac{P}{v}=\frac{0.5}{3\times 10^{8}}=0.166\times {{10}^{-8}}N/m^{2} $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक