Optics Question 324
Question: Radiations of intensity $ 0.5W/m^{2} $ are striking a metal plate. The pressure on the plate is
[DCE 2004]
Options:
A) $ 0.166\times {{10}^{-8}}N/m^{2} $
B) $ 0.332\times {{10}^{-8}}N/m^{2} $
C) $ 0.111\times {{10}^{-8}}N/m^{2} $
D) $ 0.083\times {{10}^{-8}}N/m^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
Intensity or power per unit area of the radiations $ P=fv $
Therefore $ f=\frac{P}{v}=\frac{0.5}{3\times 10^{8}}=0.166\times {{10}^{-8}}N/m^{2} $
