Optics Question 319
Question: An electromagnetic wave of frequency $ \nu =3.0MHz $ passes from vacuum into a dielectric medium with permitivity $ \varepsilon =4.0 $ . Then
[AIEEE 2004]
Options:
A) Wavelength is doubled and the frequency remains unchanged
B) Wavelength is doubled and frequency becomes half
C) Wavelength is halved and frequency remains unchanged
D) Wavelength and frequency both remain unchanged
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Answer:
Correct Answer: C
Solution:
Refractive index $ =\sqrt{\frac{\mu \varepsilon }{{\mu _{0}}{\varepsilon _{0}}}} $ Here m is not specified so we can consider m = m0 then refractive index $ =\sqrt{\frac{\varepsilon }{{\varepsilon _{0}}}}=2 $ \Speed and wavelength of wave becomes half and frequency remain unchanged.
