Optics Question 316

Question: A TV tower has a height of 100 m. The average population density around the tower is 1000 per km2. The radius of the earth is $ 6.4\times 10^{6} $ m. the population covered by the tower is

Options:

A) $ 2\times 10^{6} $

B) $ 3\times 10^{6} $

C) $ 4\times 10^{6} $

D) $ 6\times 10^{6} $

Show Answer

Answer:

Correct Answer: C

Solution:

Population covered = 2phR ´ Population density = 2p ´ 100 ´ 6.4 ´ 106 ´ $ \frac{1000}{{{(10^{3})}^{2}}} $ = 4 ´ 106



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