SATHEE: Optics Question 312

Optics Question 312

Question: An electromagnetic wave going through vacuum is described by $E = E_{0} \sin (k x - ω t)$ ; $B = B_{0} \sin (k x - ω t)$ . Which of the following equation is true

Options:

A) $E_{0} k = B_{0} ω$

B) $E_{0} ω = B_{0} k$

C) $E_{0} B_{0} = ω k$

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$\frac{E_{0}}{B_{0}} = C .$ also $k = \frac{2 π}{λ}$

and $ω = 2 π ν$ .

These relation gives $E_{0} K = B_{0} ω$

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Optics Question 312

Question: An electromagnetic wave going through vacuum is described by E=E0sin⁡(kx−ωt) ; B=B0sin⁡(kx−ωt) . Which of the following equation is true

Options:

Answer:

Solution:

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Question: An electromagnetic wave going through vacuum is described by $E = E_{0} \sin (k x - ω t)$ ; $B = B_{0} \sin (k x - ω t)$ . Which of the following equation is true