Optics Question 228

Question: A parallel beam of monochromatic light of wavelength $ 5000{AA} $ is incident normally on a single narrow slit of width 0.001 mm. The light is focused by a convex lens on a screen placed on the focal plane. The first minimum will be formed for the angle of diffraction equal to

[CBSE PMT 1993]

Options:

A) $ 0{}^\circ $

B) $ 15{}^\circ $

C) $ 30{}^\circ $

D) $ 60{}^\circ $

Show Answer

Answer:

Correct Answer: C

Solution:

For the first minima $ d\sin \theta =\lambda $

$ \Rightarrow $ $ \sin \theta =\frac{\lambda }{d}\Rightarrow $

$ \theta ={{\sin }^{-1}}( \frac{5000\times {{10}^{-10}}}{0.001\times {{10}^{-3}}} )=30^{o} $



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