Optics Question 224

Question: Direction of the first secondary maximum in the Fraunhofer diffraction pattern at a single slit is given by (a is the width of the slit)

[KCET 1999]

Options:

A) $ a\sin \theta =\frac{\lambda }{2} $

B) $ a\cos \theta =\frac{3\lambda }{2} $

C) $ a\sin \theta =\lambda $

D) $ a\sin \theta =\frac{3\lambda }{2} $

Show Answer

Answer:

Correct Answer: D

Solution:

For nth secondary maxima path difference $ d\sin \theta =(2n+1)\frac{\lambda }{2} $

$ \Rightarrow $ $ a\sin \theta =\frac{3\lambda }{2} $



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