SATHEE: Optics Question 212

Optics Question 212

Question: Light of wavelength $589.3 n m$ is incident normally on the slit of width $0.1 m m .$ What will be the angular width of the central diffraction maximum at a distance of $1 m$ from the slit

[BHU (Med.) 1999]

Options:

A) $0.68^{\circ}$

B) $1.02^{\circ}$

C) $0.34^{\circ}$

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

Angular width of central maxima $= \frac{2 λ}{d}$

$= \frac{2 \times 589.3 \times 10^{- 9}}{0.1 \times 10^{- 3}} r a d$

$= 0.0117 \times \frac{180}{π} = 0.68^{\circ}$

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Optics Question 212

Question: Light of wavelength 589.3nm is incident normally on the slit of width 0.1mm. What will be the angular width of the central diffraction maximum at a distance of 1m from the slit

Options:

Answer:

Solution:

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Question: Light of wavelength $589.3 n m$ is incident normally on the slit of width $0.1 m m .$ What will be the angular width of the central diffraction maximum at a distance of $1 m$ from the slit