Optics Question 202
Question: A single slit of width 0.20 mm is illuminated with light of wavelength 500 nm. The observing screen is placed 80 cm from the slit. The width of the central bright fringe will be
[AMU (Med.) 2002]
Options:
A) 1 mm
B) 2 mm
C) 4 mm
D) 5 mm
Show Answer
Answer:
Correct Answer: C
Solution:
Width of central bright fringe. $ =\frac{2\lambda D}{d}=\frac{2\times 500\times {{10}^{-9}}\times 80\times {{10}^{-2}}}{0.20\times {{10}^{-3}}} $
$ =4\times {{10}^{-3}}m=4mm. $
