Optics Question 183

Question: Specific rotation of sugar solution is 0.01 SI units. 200 $ kg{{m}^{-3}} $ of impure sugar solution is taken in a polarimeter tube of length 0.25m and an optical rotation of 0.4rad is observed. The percentage of purity of sugar is the sample is

[KCET 2004]

Options:

A) 80%

B) 89%

C) 11%

D) 20%

Show Answer

Answer:

Correct Answer: A

Solution:

Specific rotation $ (\alpha )=\frac{\theta }{lc}\Rightarrow c=\frac{\theta }{\alpha l}=\frac{0.4}{0.01\times 0.25}=160kg/m^{3} $

Now percentage purity of sugar solution $ =\frac{160}{200}\times 100=80% $



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