Optics Question 170

Question: The ratio of intensities of consecutive maxima in the diffraction pattern due to a single slit is

Options:

A) 1 : 4 : 9

B) 1 : 2 : 3

C) 1:49π2:425π2

D) 1:1π2:9π2

Show Answer

Answer:

Correct Answer: C

Solution:

I=I0[sinαα]2, where α=φ2 .

For nth secondary maxima dsinθ=(2n+12)λ

α=φ2=πλ[dsinθ]=(2n+12)π

I=I0[sin(2n+12)π(2n+1n)π]2=I0(2n+1)2π2 So I0:I1:I2=I0:49π2I0:425π2I0

=1:49π2:425π2



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