SATHEE: Optics Question 169

Optics Question 169

Question: In a single slit diffraction experiment first minimum for red light (660 nm) coincides with first maximum of some other wavelength l’. The value of l’ is

Options:

A) $4400 A A$

B) $6600 A A$

C) $2000 A A$

D) $3500 A A$

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Answer:

Correct Answer: A

Solution:

In a single slit diffraction experiment, position of minima is given by $d \sin θ = n λ$

So for first minima of red $\sin θ = 1 \times (\frac{λ_{R}}{d})$

and as first maxima is midway between first and second minima, for wavelength $λ^{'}$ , its position will be $d \sin θ^{'} = \frac{λ^{'} + 2 λ^{'}}{2} \Rightarrow \sin θ^{'} = \frac{3 λ^{'}}{2 d}$

According to given condition $\sin θ = \sin θ^{'}$

$\Rightarrow λ^{'} = \frac{2}{3} λ_{R}$ so $λ^{'} = \frac{2}{3} \times 6600 = 440 n m$

$= 4400 A A$

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Optics Question 169

Question: In a single slit diffraction experiment first minimum for red light (660 nm) coincides with first maximum of some other wavelength l’. The value of l’ is

Options:

Answer:

Solution:

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