Optics Question 167

Question: In a single slit diffraction of light of wavelength l by a slit of width e, the size of the central maximum on a screen at a distance b is

Options:

A) $ 2b\lambda +e $

B) $ \frac{2b\lambda }{e} $

C) $ \frac{2b\lambda }{e}+e $

D) $ \frac{2b\lambda }{e}-e $

Show Answer

Answer:

Correct Answer: C

Solution:

The direction in which the first minima occurs is $ \theta $ (say). Then $ e\sin \theta =\lambda $ or $ e\theta =\lambda $ or, $ \theta =\frac{\lambda }{e} $

$ (\because \theta =\sin \theta $ when $ \theta $ small) Width of the central maximum $ =2b\theta +e=2b.\frac{\lambda }{e}+e $



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