SATHEE: Optics Question 165

Optics Question 165

Question: A wavefront presents one, two and three HPZ at points A, B and C respectively. If the ratio of consecutive amplitudes of HPZ is 4 : 3, then the ratio of resultant intensities at these point will be

Options:

A) 169 : 16 : 256

B) 256 : 16 : 169

C) 256 : 16 : 196

D) 256 : 196 : 16

Show Answer

Answer:

Correct Answer: B

Solution:

$I_{A} = R_{1}^{2}$

$I_{B} = {(R_{1} - R_{2})}^{2} = R_{1}^{2} {(1 - \frac{R_{2}}{R_{1}})}^{2} = R_{1}^{2} {(1 - \frac{3}{4})}^{2} = \frac{R_{1}^{2}}{16}$

$I_{C} = {(R_{1} - R_{2} + R_{3})}^{2}$

$= R_{1}^{2} {(1 - \frac{R_{2}}{R_{1}} + \frac{R_{3}}{R_{1}})}^{2}$

$= R_{1}^{2} {(1 - \frac{R_{2}}{R_{1}} + \frac{R_{3}}{R_{2}} \times \frac{R_{2}}{R_{1}})}^{2}$

$= R_{1}^{2} {(1 - \frac{3}{4} + \frac{3}{4} \times \frac{3}{4})}^{2}$

$= {(\frac{13}{16})}^{2} R_{1}^{2} = \frac{169}{256} R_{1}^{2}$

$∴ I_{A} : I_{B} : I_{C} = R_{1}^{2} : \frac{R_{1}^{2}}{16} : \frac{169}{256} R_{1}^{2} = 256 : 16 : 169$

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Optics Question 165

Question: A wavefront presents one, two and three HPZ at points A, B and C respectively. If the ratio of consecutive amplitudes of HPZ is 4 : 3, then the ratio of resultant intensities at these point will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Optics Question 165

Question: A wavefront presents one, two and three HPZ at points A, B and C respectively. If the ratio of consecutive amplitudes of HPZ is 4 : 3, then the ratio of resultant intensities at these point will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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