SATHEE: Optics Question 151

Optics Question 151

Question: In a two slit experiment with monochromatic light fringes are obtained on a screen placed at some distance from the sits. If the screen is moved by $5 \times 10^{- 2} m$ towards the slits, the change in fringe width is $3 \times 10^{- 5} m$ . If separation between the slits is $10^{- 3} m$ , the wavelength of light used is

[Roorkee 1992]

Options:

A) $6000 A A$

B) $5000 A A$

C) $3000 A A$

D) $4500 A A$

Show Answer

Answer:

Correct Answer: A

Solution:

$β = \frac{λ D}{d}$

Therefore b µ D

Therefore $\frac{β_{1}}{β_{2}} = \frac{D_{1}}{D_{2}}$

Therefore $\frac{β_{1} - β_{2}}{β_{2}} = \frac{D_{1} - D_{2}}{D_{2}}$

Therefore $\frac{Δ β}{Δ D} = \frac{β_{2}}{D_{2}} = \frac{λ_{2}}{d_{2}}$

$= λ_{2} = \frac{3 \times 10^{- 5}}{5 \times 10^{- 2}} \times 10^{- 3} = 6 \times 10^{- 7} m = 6000 A A$

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Optics Question 151

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