Optics Question 150

Question: The periodic time of rotation of a certain star is 22 days and its radius is 7 ’ 108 metres. If the wavelength of light emitted by its surface be 4320AA , the Doppler shift will be (1 day = 86400 sec)

[MP PET 2001]

Options:

A) 0.033AA

B) 0.33AA

C) 3.3AA

D) 33AA

Show Answer

Answer:

Correct Answer: A

Solution:

Δλ=λ.vc where v=rω=r×(2πT)

Δλ=4320×7×108×2×3.143×108×22×86400=0.033AA



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