SATHEE: Optics Question 147

Optics Question 147

Question: The time period of rotation of the sun is 25 days and its radius is $7 \times 10^{8} m$ . The Doppler shift for the light of wavelength $6000 A A$ emitted from the surface of the sun will be

[MP PMT 1994]

Options:

A) $0.04 A A$

B) $0.40 A A$

C) $4.00 A A$

D) $40.0 A A$

Show Answer

Answer:

Correct Answer: A

Solution:

$Δ λ = λ \frac{v}{c}$ and $v = r ω$

$v = 7 \times 10^{8} \times \frac{2 π}{25 \times 24 \times 3600}, c = 3 \times 10^{8} m / s$

$∴ Δ λ = 0.04 A A$

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Optics Question 147

Question: The time period of rotation of the sun is 25 days and its radius is $7 \times 10^{8} m$ . The Doppler shift for the light of wavelength $6000 A A$ emitted from the surface of the sun will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Optics Question 147

Question: The time period of rotation of the sun is 25 days and its radius is 7×108m . The Doppler shift for the light of wavelength 6000AA emitted from the surface of the sun will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The time period of rotation of the sun is 25 days and its radius is $7 \times 10^{8} m$ . The Doppler shift for the light of wavelength $6000 A A$ emitted from the surface of the sun will be