Optics Question 143

Question: In the Young’s double slit experiment, if the phase difference between the two waves interfering at a point is f, the intensity at that point can be expressed by the expression

[MP PET 1998; MP PMT 2003]

Options:

A) $ I=\sqrt{A^{2}+B^{2}{{\cos }^{2}}\varphi } $

B) $ I=\frac{A}{B}\cos \varphi $

C) $ I=A+B\cos \frac{\varphi }{2} $

D) $ I=A+B\cos \varphi $ Where A and B depend upon the amplitudes of the two waves.

Show Answer

Answer:

Correct Answer: D

Solution:

$ I=a _{1}^{2}+a _{2}^{2}+2a _{1}a _{2}\cos \varphi $

Put $ a _{1}^{2}+a _{2}^{2}=A $

and $ a _{1}a _{2}=B;\ \ \therefore I=A+B\cos \varphi $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक