Optics Question 120

Question: A cube of side 2 m is placed in front of a concave mirror focal length 1m with its face P at a distance of 3 m and face Q at a distance of 5 m from the mirror. The distance between the images of face P and Q and height of images of P and Q are

Options:

A) 1 m, 0.5 m, 0.25 m

B) 0.5 m, 1 m, 0.25 m

C) 0.5 m, 0.25 m, 1m

D) 0.25 m, 1m, 0.5 m

Show Answer

Answer:

Correct Answer: D

Solution:

For surface P, 1v1=1f1u=113=23

Therefore v1=32m

For surface Q, 1v2=1f1u=115=45

Therefore v2=54m

v1v2=0.25m

Magnification of P=v1u=3/23=12

Height of P=12×2=1m

Magnification of Q=v2u=5/45=14

Height of Q=14×2=0.5m



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