Optics Question 1159

Question: Two slits are separated by a distance of 0.5 mm and illuminated with light of $ \lambda =6000 $ Å. If the screen is placed 2.5 m from the slits. The distance of the third bright image from the centre will be

[CPMT 2005]

Options:

A) 1.5 mm

B) 3 mm

C) 6 mm

D) 9 mm

Show Answer

Answer:

Correct Answer: D

Solution:

Distance of the nth bright fringe from the centre $ x _{n}=\frac{n\lambda D}{d} $

Therefore $ x _{3}=\frac{3\times 6000\times {{10}^{-10}}\times 2.5}{0.5\times {{10}^{-3}}}=9\times {{10}^{-3}}m=9mm. $



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