Optics Question 1146

Question: In a Young’s double slit experiment, the slit separation is 0.2 cm, the distance between the screen and slit is 1m. Wavelength of the light used is 5000 Å. The distance between two consecutive dark fringes (in mm) is

[DCE 2004]

Options:

A) 0.25

B) 0.26

C) 0.27

D) 0.28

Show Answer

Answer:

Correct Answer: A

Solution:

Distance between two consecutive dark fringes $ \beta =\frac{\lambda D}{d} $

$ =\frac{5000\times {{10}^{-10}}\times 1}{0.2\times {{10}^{-2}}}=0.25 $ mm.



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक