Optics Question 1131
Question: In Young’s double slit experiment, the intensity of light coming from the first slit is double the intensity from the second slit. The ratio of the maximum intensity to the minimum intensity on the interference fringe pattern observed is
[KCET 2002]
Options:
A) 34
B) 40
C) 25
D) 38
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\sqrt{\frac{I _{1}}{I _{2}}}+1}{\sqrt{\frac{I _{1}}{I _{2}}}-1} )}^{2}}={{( \frac{\sqrt{2}+1}{\sqrt{2}-1} )}^{2}}\approx 34; $ (given I1 = 2I2)
