Optics Question 1126
Question: In the Young’s double slit experiment with sodium light. The slits are 0.589 m a part. The angular separation of the third maximum from the central maximum will be (given l = 589 mm)
[Pb. PMT 2002]
Options:
A) $ {{\sin }^{-1}}(0.33\times 10^{8}) $
B) $ {{\sin }^{-1}}(0.33\times {{10}^{-6}}) $
C) $ {{\sin }^{-1}}(3\times {{10}^{-8}}) $
D) $ {{\sin }^{-1}}(3\times {{10}^{-6}}) $
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Answer:
Correct Answer: D
Solution:
Using relation, $ d\sin \theta =n\lambda \Rightarrow \sin \theta =\frac{n\lambda }{d} $ .
For n = 3, $ \sin \theta =\frac{3\lambda }{d}=\frac{3\times 589\times {{10}^{-9}}}{0.589} $
$ =3\times {{10}^{-6}} $ or $ \theta ={{\sin }^{-1}}(3\times {{10}^{-6}}) $
