Optics Question 1103
Question: In Young’s double slit experiment, carried out with light of wavelength l = 5000 Å, the distance between the slits is 0.2 mm and the screen is at 200 cm from the slits. The central maximum is at x =0. The third maximum (taking the central maximum as zeroth maximum) will be at x equal to
[CBSE PMT 1992; MH CET 2002]
Options:
A) 1.67 cm
B) 1.5 cm
C) 0.5 cm
D) 5.0 cm
Show Answer
Answer:
Correct Answer: B
Solution:
Distance of third maxima from central maxima is $ x=\frac{3\lambda D}{d}=\frac{3\times 5000\times {{10}^{-10}}\times (200\times {{10}^{-2}})}{0.2\times {{10}^{-3}}} $
$ =1.5cm. $
