Optics Question 1102
Question: In Young’s double slit experiment, the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be
[RPMT 1997]
Options:
A) $ 5000{AA} $
B) $ 6000{AA} $
C) $ 7000{AA} $
D) $ 8000{AA} $
Show Answer
Answer:
Correct Answer: A
Solution:
By using $ x _{n}=\frac{n\lambda D}{d} $
$ \Rightarrow (5\times {{10}^{-3}})=\frac{10\times \lambda \times 1}{(1\times {{10}^{-3}})}\Rightarrow \lambda =5\times {{10}^{-7}}m $
$ =5000{AA} $
