Optics Question 1070

Question: Two coherent light sources S1 and S2 (l= 6000 Å) are 1mm apart from each other. The screen is placed at a distance of 25 cm from the sources. The width of the fringes on the screen should be

[CPMT 1990]

Options:

A) 0.015 cm

B) 0.025 cm

C) 0.010 cm

D) 0.030 cm

Show Answer

Answer:

Correct Answer: A

Solution:

$ \beta =\frac{6000\times {{10}^{-10}}\times 25\times {{10}^{-2}}}{{{10}^{-3}}} $

$ \therefore {\lambda _{glass}}<{\lambda _{air}}\ \ (\because \ C _{glass}<C _{air}) $ .



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