Optics Question 103

Question: The average distance between the earth and moon is $ 38.6\times 10^{4} $ km. The minimum separation between the two points on the surface of the moon that can be resolved by a telescope whose objective lens has a diameter of 5 m with $ \lambda =6000\ {AA} $ is

[MP PMT 1993]

Options:

A) 5.65 m

B) 28.25 m

C) 11.30 m

D) 56.51 m

Show Answer

Answer:

Correct Answer: D

Solution:

Resolving power $ =\frac{1.22\ \lambda }{a}=\frac{1.22\times 6000\times {{10}^{-10}}}{5} $ Also resolving power $ =\frac{d}{D}=\frac{d}{38.6\times 10^{7}} $

$ \therefore \frac{1.22\times 6\times {{10}^{-7}}}{5}=\frac{d}{38.6\times 10^{7}} $

Therefore $ d=\frac{1.22\times 6\times {{10}^{-7}}\times 38.6\times 10^{7}}{5}m=56.51\ m $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक