Laws Of Motion Question 95

Question: A particle of mass m, initially at rest, is acted upon by a variable force F for a brief interval of time T. It begins to move with a velocity u after the force stops acting. F is shown in the graph as a function of time. The curve is a semicircle.

Options:

A) u=πF022m

B)u=πT28m

C) u=πF0T4m

D)u=F0T2m

Show Answer

Answer:

Correct Answer: C

Solution:

Initially particle was at rest. By the application of force its momentum increases.

Final momentum of the particle = Area of F - t graph

therefore mu= Area of semicircle mu=π r22

=π r1r22

=π (F0) (T/2)2 thereforeu=π F0T4m



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