Laws Of Motion Question 76

Question: Two forces with equal magnitudes F act on a body and the magnitude of the resultant force is F/3. The angle between the two forces is [MP PMT 1999]

Options:

A) $ {{\cos }^{-1}}( -\frac{17}{18} ) $

B) $ {{\cos }^{-1}}( -\frac{1}{3} ) $

C) $ {{\cos }^{-1}}( \frac{2}{3} ) $

D) $ {{\cos }^{-1}}( \frac{8}{9} ) $

Show Answer

Answer:

Correct Answer: A

Solution:

$ F _{ _{net}}^{2}=F _{1}^{2}+F _{2}^{2}+2F _{1}F _{2}\cos \theta $

therefore $ {{( \frac{F}{3} )}^{2}} $

$ =F^{2}+F^{2}+2F^{2}\cos \theta $

therefore $ \cos \theta =( -\frac{17}{18} ) $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक