Laws Of Motion Question 72

Question: One day on a spacecraft corresponds to 2 days on the earth. The speed of the spacecraft relative to the earth is[CBSE PMT 1993]

Options:

A) 1.5×108ms1

B) 2.1×108ms1

C) 2.6×108ms1

D) 5.2×108ms1

Show Answer

Answer:

Correct Answer: C

Solution:

T=T0[1(v2/c2)]1/2 By substituting T0= 1 day and T= 2 days we get v=2.6×108ms1



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